2(x^2+1)=5x

Solution for 2(x^2+1)=5x equation:

Simplifying
2(x2 + 1) = 5x

Reorder the terms:
2(1 + x2) = 5x
(1 * 2 + x2 * 2) = 5x
(2 + 2x2) = 5x

Solving
2 + 2x2 = 5x

Solving for variable 'x'.

Reorder the terms:
2 + -5x + 2x2 = 5x + -5x

Combine like terms: 5x + -5x = 0
2 + -5x + 2x2 = 0

Factor a trinomial.
(1 + -2x)(2 + -1x) = 0

Subproblem 1
Set the factor '(1 + -2x)' equal to zero and attempt to solve:

Simplifying
1 + -2x = 0

Solving
1 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2x = 0 + -1
-2x = 0 + -1

Combine like terms: 0 + -1 = -1
-2x = -1

Divide each side by '-2'.
x = 0.5

Simplifying
x = 0.5
Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {0.5, 2}